Class 10th Science - Complete Physics Most Important Questions🔥|  Prashant Kirad
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Class 10th Science - Complete Physics Most Important Questions🔥| Prashant Kirad

Exphub 9th &10th2h 53m1/31/2026
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❓ Q&A Guide

Factual Questions

Q1: What are the two important chapters in Class 10th Physics as mentioned in the transcript? A: The two important chapters are "Light" and "Electricity."

Q2: How many cases are there for a concave mirror according to the transcript? A: There are six cases for a concave mirror.

Q3: What is the mirror formula mentioned in the transcript? A: The mirror formula is ( \frac{1}{v} + \frac{1}{u} = \frac{1}{f} ).

Conceptual Questions

Q4: What is the significance of the "PK Trick" mentioned in the context of concave mirrors? A: The "PK Trick" is a mnemonic to remember the six cases of image formation by a concave mirror by associating specific object positions and corresponding image positions.

Q5: Why is it important to remember that the refractive index is inversely proportional to the speed of light in a medium? A: This concept is crucial because it helps in understanding how light behaves differently in various media, which is fundamental for solving problems related to refraction and refractive indices.

Analytical Questions

Q6: Analyze why a convex mirror always forms a diminished image. A: A convex mirror always forms a diminished image because it diverges light rays, making them appear to come from a point behind the mirror. This results in smaller, virtual, and erect images, which is useful for wide-angle viewing in vehicles.

Q7: Given the power formula for a lens, ( P = \frac{1}{f} ), where ( f ) is the focal length in meters, calculate the power of a lens with a focal length of 50 cm. A: The focal length in meters is 0.5 m. Therefore, the power ( P = \frac{1}{0.5} = 2 ) diopters.

Q8: If a concave mirror forms a real, inverted, and diminished image at its focus when the object is at infinity, explain the principles behind this behavior. A: When an object is at infinity, the light rays coming from it are parallel. A concave mirror converges these parallel rays to its focus, where they meet to form a real and inverted image. Since the rays are coming from a vast distance, the image formed is much smaller compared to the object.

Advanced Analytical Questions

Q9: How would you differentiate between the image formation properties of a concave lens and a convex lens? A: A concave lens diverges light rays, forming virtual, erect, and diminished images regardless of the object's position. In contrast, a convex lens converges light rays, forming real and inverted images when the object is beyond the focal length and virtual, erect, and magnified images when the object is within the focal length.

Q10: Discuss the practical applications of convex mirrors in everyday life based on their image formation properties. A: Convex mirrors are widely used in vehicles as side mirrors because they provide a wider field of view, allowing drivers to see more area behind them. This is due to the diminished and virtual nature of the images they form, which helps in better situational awareness and safety.

Q11: Using the concept of magnification in mirrors, explain why the magnification produced by a plane mirror is always +1. A: The magnification produced by a plane mirror is always +1 because the size of the image is equal to the size of the object. Plane mirrors produce images that are virtual, erect, and of the same size as the object, hence the magnification factor is +1.

Q12: Given the refractive indices of water (4/3) and glass (3/2), and the speed of light in glass as ( 2 \times 10^8 ) m/s, calculate the speed of light in water. A: Using the formula ( \frac{n_1}{n_2} = \frac{v_2}{v_1} ), where ( n_1 ) and ( n_2 ) are the refractive indices, and ( v_1 ) and ( v_2 ) are the speeds of light in the respective media: [ \frac{\frac{4}{3}}{\frac{3}{2}} = \frac{v_{water}}{2 \times 10^8} ] [ \frac{8}{9} = \frac{v_{water}}{2 \times 10^8} ] [ v_{water} = \frac{8}{9} \times 2 \times 10^8 ] [ v_{water} = \frac{16}{9} \times 10^8 ] [ v_{water} = 1.78 \times 10^8 , \text{m/s} ]

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